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Practical: Identifying Metal Ions in Solution Revision Notes | A Level AQA Chemistry

Add dilute sodium hydroxide and note the precipitate colour, add excess, then repeat with aqueous ammonia on a fresh sample. 12 questions answered.

Updated 5 Sept 2026 · Revise Right Team

Practical: Identifying Metal Ions in Solution is part of Reactions of ions in aqueous solution (A-level only) in A Level AQA Chemistry.

7 min

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26

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A Level AQA

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What this lesson covers

Add dilute sodium hydroxide and note the precipitate colour, add excess, then repeat with aqueous ammonia on a fresh sample. 12 questions answered.

  • Describe the test-tube reactions used to identify transition metal ions in aqueous solution
  • Explain the observations produced when sodium hydroxide and ammonia solutions are added to solutions of transition metal ions
  • Compare the colours and solubilities of transition metal hydroxide precipitates
  • Evaluate the results of ion identification tests and draw conclusions about the identity of an unknown metal ion

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Key ideas to keep in view

Use this lesson to stay inside Reactions of ions in aqueous solution (A-level only) while connecting the detail back to the wider Inorganic chemistry topic.

  • Transition metal ion: A metal ion formed from a d-block element (Period 4, Groups 3-12) that has an incomplete d sub-shell in at least one of its common oxidation states. These ions form characteristic coloured precipitates with hydroxide ions.
  • Hydroxide precipitate: An insoluble metal hydroxide formed when hydroxide ions are added to a solution of a metal ion. The colour of the precipitate is characteristic of the specific metal ion present.
  • Amphoteric hydroxide: A metal hydroxide that dissolves in both excess acid and excess alkali. Relevant here because certain transition metal hydroxides dissolve in excess sodium hydroxide solution, which distinguishes them from others.
  • Ligand substitution: A reaction in which one ligand in a complex ion is replaced by another. Occurs when excess ammonia is added to some transition metal hydroxide precipitates, causing them to dissolve and form a new soluble complex.

Revision notes

Read the core explanations from Practical: Identifying Metal Ions in Solution before testing yourself from memory.

1. Why Identifying Metal Ions Matters

Picture this: you have a colourless or pale solution and you need to determine which transition metal ion it contains. You cannot see inside the solution at the atomic level — but you can provoke it into revealing itself through a series of simple test-tube reactions.

This is the heart of Required Practical 11. The reactions you carry out are not arbitrary — each one exploits a specific chemical property of transition metal ions, and the colour and behaviour of the precipitate you observe is your evidence. Getting this right in an exam means knowing not just what you see, but why you see it.

2. The Chemistry Behind the Colours

Transition metal ions in aqueous solution exist as aqua complexes — the metal ion is surrounded by six water molecules acting as ligands, giving the general form $[M(H_2O)_6]^{n+}$. The colour of these aqua complexes arises because d-electrons absorb specific wavelengths of visible light when they are promoted between split d-orbitals.

When you add sodium hydroxide solution ($NaOH$) or aqueous ammonia ($NH_3$) to these complexes, the $OH^-$ or $NH_3$ ligands displace the water molecules. The result is a precipitate or a new soluble complex — and the colour change is your diagnostic signal.

The key insight is that each transition metal ion produces a distinctive colour of precipitate with $OH^-$ ions, and some of those precipitates then behave differently when you add excess reagent. That two-stage behaviour — initial precipitate, then response to excess — is what allows you to distinguish between ions that might otherwise look similar.

3. Reactions with Sodium Hydroxide Solution

Adding a few drops of dilute sodium hydroxide solution to a transition metal ion solution introduces $OH^-$ ions. These react with the aqua complex, replacing water ligands and causing the metal hydroxide to precipitate out of solution. The general equation follows this pattern:

Metal IonAqua Complex ColourPrecipitate with NaOHPrecipitate ColourBehaviour with Excess NaOH
$Cu^{2+}$Pale blue$Cu(OH)_2(s)$BlueNo change — precipitate remains
$Fe^{2+}$Pale green$Fe(OH)_2(s)$GreenNo change — precipitate remains
$Fe^{3+}$Yellow/brown$Fe(OH)_3(s)$Reddish-brownNo change — precipitate remains
$Cr^{3+}$Green/violet$Cr(OH)_3(s)$Grey-greenDissolves in excess — forms $[Cr(OH)_4]^-(aq)$ (dark green)
$Co^{2+}$Pink$Co(OH)_2(s)$Blue/greenNo change — precipitate remains
$Mn^{2+}$Very pale pink$Mn(OH)_2(s)$Buff/off-whiteNo change — precipitate remains

The behaviour of $Cr^{3+}$ with excess $NaOH$ is particularly important. Chromium(III) hydroxide is amphoteric — it dissolves in excess alkali to form the tetrahydroxochromate(III) ion, $[Cr(OH)_4]^-(aq)$, which is dark green. This distinguishes $Cr^{3+}$ from all other common transition metal ions in this test.

4. Reactions with Aqueous Ammonia

Aqueous ammonia ($NH_3(aq)$) acts as both a weak base and a ligand. As a weak base, it partially ionises in water to provide $OH^-$ ions — but at a much lower concentration than sodium hydroxide. These $OH^-$ ions are sufficient to precipitate the metal hydroxide, so when you add a small amount of ammonia solution, you still get the same coloured hydroxide precipitate as with $NaOH$. The diagnostic difference comes when you add excess ammonia.

Ammonia is also a ligand. In excess, it can displace water molecules from the metal complex through ligand substitution, forming a new soluble ammine complex. This dissolves the precipitate and produces a characteristic colour change — and that colour change is your key distinguishing observation.

Metal IonPrecipitate with Dilute $NH_3$Precipitate ColourBehaviour with Excess $NH_3$
$Cu^{2+}$$Cu(OH)_2(s)$BlueDissolves to give deep blue solution — $[Cu(NH_3)_4(H_2O)_2]^{2+}(aq)$
$Fe^{2+}$$Fe(OH)_2(s)$GreenNo change — precipitate remains
$Fe^{3+}$$Fe(OH)_3(s)$Reddish-brownNo change — precipitate remains
$Cr^{3+}$$Cr(OH)_3(s)$Grey-greenDissolves to give violet/purple solution — $[Cr(NH_3)_6]^{3+}(aq)$
$Co^{2+}$$Co(OH)_2(s)$Blue/greenDissolves to give straw-yellow/brown solution — $[Co(NH_3)_6]^{2+}(aq)$
$Mn^{2+}$$Mn(OH)_2(s)$Buff/off-whiteNo change — precipitate remains

Notice that $Cu^{2+}$ is uniquely identified by the deep blue tetraamminediaquacopper(II) complex formed in excess ammonia. No other common transition metal ion produces this intense deep blue colour, making it one of the most reliable identification tests at A-level.

5. Distinguishing Between Similar Ions

Several pairs of ions can look deceptively similar at first glance, and examiners know this. The table below highlights the most commonly confused pairs and the observations that separate them.

PairWith NaOHWith Excess NaOHWith Excess $NH_3$Key Distinguishing Test
$Fe^{2+}$ vs $Fe^{3+}$$Fe^{2+}$: green ppt; $Fe^{3+}$: reddish-brown pptNeither dissolvesNeither dissolvesColour of precipitate with NaOH is definitive
$Cu^{2+}$ vs $Co^{2+}$Both give blue/blue-green pptNeither dissolves$Cu^{2+}$ gives deep blue solution; $Co^{2+}$ gives straw-yellow/brown solutionExcess ammonia is the definitive test
$Cr^{3+}$ vs othersGrey-green pptDissolves to dark green solutionDissolves to violet/purple solutionDissolution in excess NaOH is unique to $Cr^{3+}$

The $Fe^{2+}$/$Fe^{3+}$ distinction is one of the most reliable in this practical — the green versus reddish-brown precipitate colours are visually distinct and do not require any further testing. For $Cu^{2+}$ versus $Co^{2+}$, however, the initial precipitate colours can overlap, so always proceed to the excess ammonia test.

6. Required Practical 11 — Procedure and Evaluation

Required Practical 11 asks you to carry out systematic test-tube reactions to identify transition metal ions in aqueous solution. The procedure follows a logical sequence: first test with dilute NaOH, observe the precipitate colour, then add excess NaOH and record any change, then repeat the sequence with aqueous ammonia on a fresh sample.

One practical consideration worth noting: $Fe^{2+}$ precipitates can oxidise in air over time, turning from green $Fe(OH)_2$ towards reddish-brown $Fe(OH)_3$. If you observe a green precipitate that darkens on standing, this is consistent with $Fe^{2+}$ — and it is worth mentioning this in an exam evaluation question as a source of ambiguity.

Worked example: Systematic Identification of an Unknown Transition Metal Ion

An unknown solution produces a blue-green precipitate when dilute NaOH is added. The precipitate does not dissolve in excess NaOH. When the test is repeated with aqueous ammonia, the same blue-green precipitate forms initially, then dissolves in excess ammonia to give a straw-yellow/brown solution. Identify the ion and write the ionic equation for the formation of the precipitate.

  1. Blue-green precipitate with NaOH, does not dissolve in excess. — This rules out $Cr^{3+}$ (which dissolves in excess NaOH to give dark green). The blue-green colour is consistent with $Co^{2+}$ or possibly $Cu^{2+}$, though $Cu^{2+}$ typically gives a more distinctly blue precipitate.
  2. Precipitate dissolves in excess $NH_3$ to give straw-yellow/brown solution. — This is the key distinguishing observation. $Cu^{2+}$ would give a deep blue solution in excess ammonia. A straw-yellow/brown solution is characteristic of $[Co(NH_3)_6]^{2+}$, confirming the ion is $Co^{2+}$.
  3. Ion = $Co^{2+}$ — The combination of blue-green precipitate with NaOH (no dissolution in excess) and dissolution in excess ammonia to give straw-yellow/brown solution is unique to cobalt(II).
  4. $[Co(H_2O)_6]^{2+}(aq) + 2OH^-(aq) \rightarrow Co(OH)_2(s) + 6H_2O(l)$ — The aqua complex loses two water ligands and gains two $OH^-$ ions, forming the insoluble cobalt(II) hydroxide precipitate. State symbols are required for full marks.

Answer: The ion is $Co^{2+}$. Ionic equation: $[Co(H_2O)_6]^{2+}(aq) + 2OH^-(aq) \rightarrow Co(OH)_2(s) + 6H_2O(l)$

7. Exam Technique and Common Mistakes

AQA exam questions on this practical tend to fall into two categories: recall of specific observations, and application to an unknown ion scenario. Both require precise language — vague answers like "a coloured precipitate forms" will not score marks. You need to name the colour and state whether it dissolves in excess reagent.

When writing ionic equations for these reactions, always include state symbols and write the metal ion as its aqua complex $[M(H_2O)_6]^{n+}$ if the question asks for the full ionic equation. If the question asks for a simplified ionic equation, you may omit the water ligands — but check the command word carefully.

Required Practical 11 tests your ability to carry out systematic test-tube reactions and interpret observations precisely — both skills that appear directly in AQA exam questions, whether as short 'describe' tasks or extended 'explain and identify' scenarios. Mastering the colour of each precipitate, the behaviour with excess reagent, and the ionic equations that underpin each observation gives you complete coverage of this specification requirement.

Frequently asked questions

What is the procedure for Required Practical 11?

Required Practical 11 identifies transition metal ions by test-tube reactions: add dilute NaOH, note the precipitate colour, add excess NaOH and record any change, then repeat with aqueous ammonia on a fresh sample. The precipitate colour and its response to excess reagent identify the ion.

How do you identify transition metal ions in solution?

To identify a transition metal ion, add a few drops of dilute sodium hydroxide and note the precipitate colour, add excess NaOH and record any change, then repeat with aqueous ammonia on a fresh sample, adding excess. The colour of each precipitate and whether it dissolves in excess identify the ion.

How do you tell Fe2+ from Fe3+?

Fe²⁺ and Fe³⁺ are distinguished by the colour of their hydroxide precipitates with sodium hydroxide: Fe²⁺ gives a green Fe(OH)₂ precipitate and Fe³⁺ a reddish-brown Fe(OH)₃ precipitate. Neither dissolves in excess NaOH or ammonia, and green Fe(OH)₂ darkens on standing as it oxidises in air.

How do you tell copper(II) ions from cobalt(II) ions?

Cu²⁺ and Co²⁺ can both give blue or blue-green precipitates with sodium hydroxide, so excess ammonia is the definitive test. Copper's precipitate dissolves to give a deep blue solution of [Cu(NH₃)₄(H₂O)₂]²⁺, while cobalt's dissolves to give a straw-yellow/brown solution of [Co(NH₃)₆]²⁺.

What happens when sodium hydroxide is added to chromium(III) ions?

Sodium hydroxide gives a grey-green Cr(OH)₃ precipitate with Cr³⁺. Chromium(III) hydroxide is amphoteric, so it dissolves in excess NaOH to form dark green [Cr(OH)₄]⁻, and in excess ammonia it dissolves to give a violet/purple solution of [Cr(NH₃)₆]³⁺.

Why does excess ammonia dissolve some metal hydroxide precipitates?

Aqueous ammonia acts as a weak base and as a ligand. In small amounts it provides OH⁻ ions that precipitate the metal hydroxide; in excess, ammonia molecules displace water ligands by ligand substitution, forming a soluble ammine complex that dissolves the precipitate, as with Cu²⁺, Cr³⁺ and Co²⁺.

What happens when excess ammonia is added to chromium(III) ions?

Chromium(III) ions give a grey-green Cr(OH)₃ precipitate with dilute ammonia, which dissolves in excess ammonia to give a violet or purple solution of [Cr(NH₃)₆]³⁺. Ammonia acts first as a base and then as a ligand.

What colour does cobalt(II) hydroxide turn in excess ammonia?

Cobalt(II) hydroxide, a blue-green precipitate, dissolves in excess ammonia to give a straw-yellow or brown solution of [Co(NH₃)₆]²⁺. This distinguishes Co²⁺ from Cu²⁺, which gives a deep blue solution in excess ammonia.

What happens when sodium hydroxide is added to manganese(II) ions?

Mn²⁺ ions, which are very pale pink in solution, give a buff or off-white Mn(OH)₂ precipitate with sodium hydroxide. The precipitate does not dissolve in excess NaOH or in excess ammonia.

Why does iron(II) hydroxide turn brown on standing?

Green iron(II) hydroxide, Fe(OH)₂, darkens on standing because it oxidises in air towards reddish-brown Fe(OH)₃. A green precipitate that darkens is still consistent with Fe²⁺, and this is worth mentioning as a source of ambiguity in evaluation questions.

What is the equation for cobalt(II) hydroxide forming?

The ionic equation for cobalt(II) hydroxide forming is [Co(H₂O)₆]²⁺(aq) + 2 OH⁻(aq) → Co(OH)₂(s) + 6 H₂O(l). The aqua complex loses its water ligands as two OH⁻ ions react with it, giving the insoluble blue-green precipitate.

Why does chromium(III) hydroxide dissolve in excess sodium hydroxide?

Chromium(III) hydroxide dissolves in excess sodium hydroxide because it is amphoteric, forming the dark green tetrahydroxochromate(III) ion, [Cr(OH)₄]⁻(aq). This dissolution in excess NaOH distinguishes Cr³⁺ from the other common transition metal ions.

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