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Introduction to SI Units Revision Notes | A Level AQA Physics

A newton is kg m s⁻² in base units, and a joule, from W = F × d, is kg m² s⁻². Free A Level AQA Physics notes with 3 worked examples and 14 questions answered.

Updated 12 Sept 2026 · Revise Right Team

Introduction to SI Units is part of Use of SI units and their prefixes in A Level AQA Physics.

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What this lesson covers

A newton is kg m s⁻² in base units, and a joule, from W = F × d, is kg m² s⁻². Free A Level AQA Physics notes with 3 worked examples and 14 questions answered.

  • State the seven SI base units and identify the six required for A Level Physics (excluding the candela)
  • Recall the SI base units for mass, length, time, amount of substance, temperature, and electric current
  • Derive SI units for common physical quantities from base units
  • Apply SI prefix multipliers to convert between units in calculations

Key ideas to keep in view

Use this lesson to stay inside Use of SI units and their prefixes while connecting the detail back to the wider Measurements and their errors topic.

  • SI base unit: One of the seven internationally agreed fundamental units from which all other units are derived. Each base unit measures a single, independent physical quantity.
  • Derived unit: A unit formed by combining two or more SI base units through multiplication or division, corresponding to a physical quantity defined by a formula.
  • SI prefix: A multiplier attached to a unit symbol to represent powers of ten, allowing very large or very small quantities to be expressed concisely.
  • Homogeneity of units: The principle that every term in a valid physical equation must have identical base units on both sides. Used to verify equations and check working.

Revision notes

Read the core explanations from Introduction to SI Units before testing yourself from memory.

1. Why a Universal Language of Measurement Matters

Imagine two physicists — one in Tokyo, one in Manchester — measuring the same electric current but recording it in different units. Their results would be meaningless to each other. The International System of Units (SI), from the French Système International d'Unités, solves this by giving every scientist on Earth the same measurement language.

At A Level, you will encounter quantities ranging from the mass of a proton ($1.67 \times 10^{-27}$ kg) to the distance to a nearby star ($4 \times 10^{16}$ m). Without a coherent unit system and a set of agreed prefixes, comparing or combining these numbers would be impossible. Every equation you use this year ultimately traces back to a small set of base units.

2. The SI Base Units You Need to Know

There are seven SI base units in total. For AQA A Level Physics, you are required to know six of them — the candela (the unit of luminous intensity) is explicitly excluded from your specification. You do not need to memorise the formal definitions of these quantities, but you must know which unit belongs to which quantity.

Physical QuantitySI Base UnitSymbol
Masskilogramkg
Lengthmetrem
Timeseconds
Electric currentampereA
TemperaturekelvinK
Amount of substancemolemol

Notice that temperature uses the kelvin, not the degree Celsius. The kelvin scale starts at absolute zero (0 K = −273.15 °C), which makes it the physically meaningful choice for equations such as the ideal gas law. When a question gives temperature in °C, convert it: $T(\text{K}) = T(°\text{C}) + 273$.

The mole deserves a special mention. It is the SI unit for amount of substance — a count of particles (atoms, molecules, ions, electrons) expressed in units of Avogadro's number ($N_A = 6.02 \times 10^{23}$ mol$^{-1}$). You will use it whenever you connect macroscopic measurements to particle-level behaviour.

That retrieval attempt is worth doing seriously — examiners regularly award a straightforward mark for correctly stating a base unit, and students frequently lose it by writing °C instead of K, or by confusing the symbol for ampere (A) with the symbol for area.

3. Building Derived Units from Base Units

Every other unit in physics is a derived unit — built by multiplying or dividing base units according to the defining equation for that quantity. This is not just bookkeeping; it is a powerful consistency check. If the units on both sides of your equation do not match, something in your working is wrong.

Start with something familiar: speed. Speed is defined as distance divided by time, so its unit is metres divided by seconds — written as m s$^{-1}$ (or equivalently m/s). The unit follows directly from the formula, with no extra information needed.

Now consider a more complex case: the newton (N), the unit of force. Newton's second law states $F = ma$, so force has units of kg × m s$^{-2}$. The newton is therefore shorthand for kg m s$^{-2}$. Whenever you see a named derived unit — newton, joule, pascal, watt — you can always unpack it into base units.

QuantitySymbolDefining EquationIn Base Units
ForceN$F = ma$kg m s$^{-2}$
Energy / WorkJ$W = Fd$kg m$^{2}$ s$^{-2}$
PowerW$P = W/t$kg m$^{2}$ s$^{-3}$
PressurePa$p = F/A$kg m$^{-1}$ s$^{-2}$
ChargeC$Q = It$A s
VoltageV$V = W/Q$kg m$^{2}$ s$^{-3}$ A$^{-1}$
Resistance\(\Omega\)$R = V/I$kg m$^{2}$ s$^{-3}$ A$^{-2}$

You do not need to memorise every row of that table. What you need is the method: start from the defining equation, substitute the units of each quantity, and simplify. The step-by-step walkthrough below shows exactly how to do this under exam conditions.

Worked example: Deriving the Base Units of the Joule

Show that the joule (J), the unit of energy, is equivalent to kg m$^{2}$ s$^{-2}$ in base units.

  1. $W = F \times d$ — Work done equals force multiplied by displacement. This is the equation that defines the joule. [M1]
  2. Unit of $F$ = N = kg m s$^{-2}$ — The newton is itself a derived unit. Unpack it using $F = ma$: unit of $a$ is m s$^{-2}$, so unit of $F$ is kg × m s$^{-2}$.
  3. Unit of $d$ = m — Displacement is a length — a base unit, so no unpacking needed.
  4. Unit of $W$ = kg m s$^{-2}$ × m = kg m$^{2}$ s$^{-2}$ — Combine by adding exponents for matching base units: m$^{1}$ × m$^{1}$ = m$^{2}$. [A1]
  5. 1 J = 1 kg m$^{2}$ s$^{-2}$ — This is the accepted base-unit expression for the joule. Any quantity with these base units is an energy.

Answer: 1 J = 1 kg m$^{2}$ s$^{-2}$

4. SI Prefixes: Scaling Units for the Real World

Physics spans an enormous range of scales. Writing $0.000000001$ m every time you refer to a nanometre is impractical and error-prone. SI prefixes attach to any unit to shift its scale by a defined power of ten, keeping numbers manageable without changing the underlying measurement.

PrefixSymbolMultiplierPower of Ten
teraT1 000 000 000 000$10^{12}$
gigaG1 000 000 000$10^{9}$
megaM1 000 000$10^{6}$
kilok1 000$10^{3}$
(none)—1$10^{0}$
millim0.001$10^{-3}$
micro$\mu$0.000 001$10^{-6}$
nanon0.000 000 001$10^{-9}$
picop0.000 000 000 001$10^{-12}$

The prefix replaces the power of ten in your number. So 5 km means $5 \times 10^{3}$ m, and 300 nm means $300 \times 10^{-9}$ m = $3.00 \times 10^{-7}$ m. Before substituting into any equation, always convert prefixed units back to their SI base form — this is where a large proportion of unit-conversion errors originate in exam scripts.

Worked example: Converting Prefixed Units Before Calculation

A resistor dissipates a power of 2.0 mW when a current of 4.0 mA flows through it. Calculate the resistance of the resistor in ohms.

  1. $P = 2.0 \text{ mW} = 2.0 \times 10^{-3} \text{ W}$ — The prefix milli means $10^{-3}$. Replace mW with $\times 10^{-3}$ W before proceeding. [M1]
  2. $I = 4.0 \text{ mA} = 4.0 \times 10^{-3} \text{ A}$ — Again, milli = $10^{-3}$. Both quantities are now in SI base units.
  3. $P = I^{2} R \quad \Rightarrow \quad R = \frac{P}{I^{2}}$ — Rearrange for resistance. [M1]
  4. $I^{2} = (4.0 \times 10^{-3})^{2} = 4.0 \times 10^{-3} \times 4.0 \times 10^{-3} = 16 \times 10^{-6} = 1.6 \times 10^{-5} \text{ A}^{2}$ — Expand the square explicitly: $4.0 \times 4.0 = 16$ and $10^{-3} \times 10^{-3} = 10^{-6}$.
  5. $R = \frac{2.0 \times 10^{-3}}{1.6 \times 10^{-5}} = \frac{2.0}{1.6} \times 10^{-3-(-5)} = 1.25 \times 10^{2} = 125 \text{ } \Omega$ — Divide the coefficients ($2.0 \div 1.6 = 1.25$) and subtract exponents ($-3 - (-5) = +2$). [A1]
  6. Unit of $R$: $\frac{\text{W}}{\text{A}^{2}} = \frac{\text{kg m}^{2} \text{s}^{-3}}{\text{A}^{2}} = \text{kg m}^{2} \text{s}^{-3} \text{A}^{-2} = \Omega$ ✓ — The unit of the answer matches the ohm expressed in base units, confirming the formula was applied correctly.

Answer: $R = 125 \ \Omega$

5. Using Base Units to Check Equations

Earlier you saw how to derive the base units of a quantity from its defining equation. That same process works in reverse: you can check whether an unfamiliar equation is homogeneous — meaning the base units on the left-hand side match those on the right-hand side. If they do not match, the equation is definitely wrong. If they do match, the equation is at least dimensionally consistent (though it could still have a missing numerical constant).

This technique is sometimes called a unit check or unit analysis. AQA does not require you to perform formal dimensional analysis, but checking units is an expected part of good exam technique and is often rewarded implicitly when you show your working clearly.

Worked example: Checking Homogeneity: Kinetic Energy Formula

Verify that the equation $E_k = \frac{1}{2}mv^{2}$ is homogeneous in SI base units.

  1. Unit of $E_k$ = J = kg m$^{2}$ s$^{-2}$ — Energy is measured in joules. From the earlier derivation, 1 J = 1 kg m$^{2}$ s$^{-2}$.
  2. Unit of $m$ = kg — Mass is a base quantity — no derivation needed.
  3. Unit of $v$ = m s$^{-1}$, so unit of $v^{2}$ = (m s$^{-1}$)$^{2}$ = m$^{2}$ s$^{-2}$ — Square both the unit of distance and the unit of time: m$^{1 \times 2}$ = m$^{2}$ and s$^{-1 \times 2}$ = s$^{-2}$.
  4. Unit of $\frac{1}{2}mv^{2}$ = kg × m$^{2}$ s$^{-2}$ = kg m$^{2}$ s$^{-2}$ — The numerical factor $\frac{1}{2}$ is dimensionless and does not affect the unit check.
  5. LHS: kg m$^{2}$ s$^{-2}$ = RHS: kg m$^{2}$ s$^{-2}$ ✓ — The units match, so the equation is homogeneous. This confirms the formula is dimensionally consistent.

Answer: The equation $E_k = \frac{1}{2}mv^{2}$ is homogeneous; both sides have units of kg m$^{2}$ s$^{-2}$.

6. Exam Technique: Getting Every Mark on Units Questions

Unit questions appear in two main forms at A Level: state the unit (one mark, no working required) and show that the unit of [quantity] is [base units] (two or three marks, working required). The second type is where students most often drop marks — not because they lack knowledge, but because they skip steps that the mark scheme rewards explicitly.

For a show that question, write out the defining equation, substitute the unit of each variable, and simplify step by step. Never go straight from the equation to the answer in one line — the method marks are in the intermediate steps. For a calculate question involving prefixed units, show the conversion explicitly as a separate line before substituting.

When a question asks you to state a base unit, give both the full name and the symbol if the question is ambiguous about which it wants. Writing 'kilogram (kg)' takes two seconds and removes any doubt. Examiners accept either, but clarity never costs marks.

That question targets the two most common confusions: treating named derived units (newton, joule) as base units, and including the candela because it sounds like it should be on the list. Both errors reflect a misunderstanding of what 'base unit' means — a unit that cannot be broken down further into other SI units.

7. Bringing It Together: A Unit-Consistency Checklist

Every calculation you carry out this year should pass through the same mental checklist. This is not extra work — it is the habit that separates students who consistently score full marks on calculation questions from those who drop one or two marks through avoidable unit errors.

  • Identify every quantity in the equation and note its unit.
  • Convert any prefixed units to SI base units before substituting (show this conversion as a separate line).
  • Substitute values with units attached — never substitute bare numbers.
  • After calculating, check that the unit of your answer matches the expected unit for that quantity.
  • If the question asks you to express a unit in base form, start from the defining equation and work through each variable systematically.
  • For temperature: confirm whether the equation requires kelvin or accepts Celsius, and convert if necessary.

The six base units — kilogram, metre, second, ampere, kelvin, and mole — are the foundation on which every other unit in your A Level course is built. Mastering their symbols, their associated quantities, and the method for deriving units from equations gives you a reliable self-checking tool that works across every topic, from mechanics to electromagnetism to thermal physics.

Frequently asked questions

How do you show the joule is kg m² s⁻²?

Start from the defining equation W = F × d. The unit of force is kg m s⁻² and the unit of displacement is m, so multiplying them gives kg m² s⁻². Therefore 1 J = 1 kg m² s⁻².

What is a newton in SI base units?

A newton is kg m s⁻² in base units. Newton's second law gives F = ma, so the unit of force is the unit of mass, kg, multiplied by m s⁻², the unit of a.

What is a volt in SI base units?

The volt is kg m² s⁻³ A⁻¹ in base units. Voltage is energy per unit charge, V = W/Q, so the joule, kg m² s⁻², is divided by the unit of charge, A s, giving kg m² s⁻³ A⁻¹.

What is a watt in SI base units?

The watt is kg m² s⁻³ in base units. Power is work done divided by time, P = W/t, so the base units of the joule, kg m² s⁻², are divided by seconds to give kg m² s⁻³.

What is a derived unit?

A derived unit is built by multiplying or dividing base units according to the defining equation for a quantity. Speed is distance divided by time, so its unit is m s⁻¹, and the newton, joule, pascal and watt are named derived units.

What are the SI base units for A Level Physics?

A Level Physics uses six of the seven SI base units: kilogram (kg) for mass, metre (m) for length, second (s) for time, ampere (A) for electric current, kelvin (K) for temperature and mole (mol) for amount of substance. The candela is the one excluded.

What is an ohm in SI base units?

The ohm is kg m² s⁻³ A⁻² in base units. Resistance is voltage divided by current, R = V/I, so the base units of the volt, kg m² s⁻³ A⁻¹, are divided by A.

Why does physics use kelvin instead of degrees Celsius?

The kelvin is the SI base unit of temperature, and its scale starts at absolute zero, where 0 K = −273.15 °C. That makes it the physically meaningful choice for equations such as the ideal gas law, so convert with T(K) = T(°C) + 273.

How do you check if an equation is homogeneous?

Express both sides of the equation in SI base units and compare them. For kinetic energy, ½mv², the left side is kg m² s⁻² and the right side is kg × m² s⁻², so the equation is homogeneous. Numerical factors such as ½ have no unit and do not affect the check.

What is a pascal in SI base units?

The pascal is kg m⁻¹ s⁻² in base units. Pressure is force divided by area, p = F/A, so the newton, kg m s⁻², divided by m² gives kg m⁻¹ s⁻².

Is the newton a base unit?

The newton is a derived unit, not a base unit. A base unit cannot be broken down further into other SI units, but the newton unpacks from F = ma into kg m s⁻².

What are the base units of charge?

Charge has base units of A s, because Q = It: current in amperes multiplied by time in seconds. The ampere is a base unit, so charge needs no further unpacking.

Does a homogeneous equation have to be correct?

A homogeneous equation is dimensionally consistent, but it could still have a missing numerical constant, so it might still be wrong. If the base units on the two sides do not match, the equation is definitely wrong.

How many electrons per second make 1 ampere?

As a conceptual description, 1 A corresponds to approximately 6.24 × 10¹⁸ elementary charges per second past a point. This is a consequence of the 2019 SI definition, which fixes the elementary charge exactly.

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