Revise Right
Hold tight Hi there!

✓ Revise Right course

Electromagnetic Induction: Experiments & Laws Revision Notes | A Level AQA Physics

Faraday's law of electromagnetic induction states that the induced EMF equals the rate of change of flux linkage: ε = -Δ(NΦ)/Δt. 12 questions answered.

Updated 12 Sept 2026 · Revise Right Team

Electromagnetic Induction: Experiments & Laws is part of Magnetic fields (A-level only) in A Level AQA Physics.

7 min

Reading time

31

Lessons in this topic

A Level AQA

Pathway

Reviewed by Revise Right

Content review

What this lesson covers

Faraday's law of electromagnetic induction states that the induced EMF equals the rate of change of flux linkage: ε = -Δ(NΦ)/Δt. 12 questions answered.

  • Describe the experimental phenomena that demonstrate electromagnetic induction, including the effect of moving a magnet relative to a coil
  • State Faraday's law of electromagnetic induction and apply it to calculate induced EMF
  • State Lenz's law and use it to predict the direction of an induced current
  • Explain how Faraday's and Lenz's laws together govern the behaviour of induced EMF and current in practical situations

Key ideas to keep in view

Use this lesson to stay inside Magnetic fields (A-level only) while connecting the detail back to the wider Fields and their consequences (A-level only) topic.

  • Electromagnetic induction: The process by which a changing magnetic flux through a conductor produces an EMF (electromotive force) in that conductor.
  • Magnetic flux linkage: The product of the magnetic flux through a coil and the number of turns, given by $N\Phi = BAN\cos\theta$. Measured in weber-turns (Wb).
  • Faraday's law: The magnitude of the induced EMF in a circuit is equal to the rate of change of flux linkage: $\varepsilon = -\frac{\Delta(N\Phi)}{\Delta t}$.
  • Lenz's law: The direction of the induced current is always such that it opposes the change in flux that caused it, consistent with conservation of energy.

Revision notes

Read the core explanations from Electromagnetic Induction: Experiments & Laws before testing yourself from memory.

1. The Phenomenon: Why Does a Moving Magnet Produce a Current?

Picture a coil of wire connected to a sensitive galvanometer. The coil is sitting still, the needle reads zero. Now push a bar magnet into the coil — the needle deflects. Pull the magnet out — it deflects the other way. Hold the magnet stationary inside the coil — the needle returns to zero. That sequence of observations is electromagnetic induction, and every rule in this topic flows from it.

The key variable is not the presence of a magnetic field, but the change in the magnetic flux passing through the coil. Flux, given the symbol $\Phi$, measures how much of the magnetic field threads through a given area. When that threading changes — because the magnet moves, the coil moves, or the field strength changes — an EMF is induced.

When a coil has $N$ turns, every turn contributes its own flux. The total is called the flux linkage: $N\Phi$. Doubling the number of turns doubles the flux linkage for the same field — and, as you will see, doubles the induced EMF for the same rate of change. This is why real transformers and generators use many-turn coils rather than a single loop.

2. Mapping the Experimental Phenomena

Before formalising the laws, it is worth cataloguing exactly what the experiments show, because AQA questions often ask you to describe or explain observations rather than quote a formula. The table below summarises the classic magnet-and-coil results.

ActionObservationWhat is changing?
Magnet pushed into coil (N pole first)Galvanometer deflects in one direction; current flowsFlux linkage through coil is increasing
Magnet held stationary inside coilGalvanometer reads zero; no currentFlux linkage is constant — no change
Magnet pulled out of coilGalvanometer deflects in the opposite directionFlux linkage through coil is decreasing
Magnet pushed in fasterLarger deflection; greater induced EMFRate of change of flux linkage is greater
Coil with more turns usedLarger deflection for the same magnet speedGreater flux linkage change per unit time
S pole pushed in (instead of N pole)Deflection in the opposite direction to N pole entryDirection of flux change is reversed

Every row in that table is a direct experimental test of Faraday's law. The magnitude of the deflection tracks the rate of flux linkage change; the direction of the deflection tracks the sign of that change. These two strands become the two laws you need to master.

3. Faraday's Law: Quantifying the Induced EMF

Faraday's law takes the experimental pattern — bigger rate of change gives bigger EMF — and turns it into a precise, calculable relationship. The induced EMF equals the rate of change of flux linkage.

Notice that the formula contains $N\Phi$ as a single quantity — the flux linkage — not $N$ and $\Phi$ separately. This matters when the number of turns is fixed (as it usually is) and only $\Phi$ changes: you can write $\varepsilon = -N\frac{\Delta\Phi}{\Delta t}$. Both forms are equivalent; use whichever the question gives you data for.

The gradient of a flux linkage–time graph gives the induced EMF directly. A steep gradient means a large EMF; a flat section (constant flux linkage) means zero EMF. This graph-reading skill appears regularly in AQA data questions.

Worked example: Calculating Induced EMF Using Faraday's Law

A coil of 200 turns has a cross-sectional area of $4.0 \times 10^{-4}$ m². A uniform magnetic field perpendicular to the coil increases from 0.10 T to 0.55 T in 0.030 s. Calculate the magnitude of the induced EMF. [3 marks]

  1. $|\varepsilon| = N\frac{\Delta\Phi}{\Delta t}$ — [M1] Selecting the correct formula. Since $N$ is constant and the field is perpendicular to the coil, $\Delta\Phi = \Delta B \times A$.
  2. $\Delta\Phi = \Delta B \times A = (0.55 - 0.10) \times 4.0 \times 10^{-4}$ $\Delta\Phi = 0.45 \times 4.0 \times 10^{-4} = 1.8 \times 10^{-4}$ Wb — The field is perpendicular to the coil so $\cos\theta = 1$ and $\Phi = BA$. The change in $B$ is $0.55 - 0.10 = 0.45$ T.
  3. $|\varepsilon| = 200 \times \frac{1.8 \times 10^{-4}}{0.030}$ — [M1] Correct substitution with $N = 200$, $\Delta\Phi = 1.8 \times 10^{-4}$ Wb, $\Delta t = 0.030$ s.
  4. $\frac{1.8 \times 10^{-4}}{0.030} = 6.0 \times 10^{-3}$ V per turn $|\varepsilon| = 200 \times 6.0 \times 10^{-3} = 1.2$ V — [A1] Division: $1.8 \times 10^{-4} \div 3.0 \times 10^{-2} = 6.0 \times 10^{-3}$. Then $200 \times 6.0 \times 10^{-3} = 1.2$ V. Units check: Wb s$^{-1}$ = V. Correct.

Answer: $|\varepsilon| = 1.2$ V

4. Lenz's Law: The Direction of the Induced Current

Faraday's law tells you how much EMF is induced. Lenz's law tells you which way the current flows. The two laws are inseparable in practice, and the negative sign in Faraday's equation is the mathematical expression of Lenz's law.

Here is how to apply Lenz's law step by step. First, identify whether the flux through the coil is increasing or decreasing. Second, determine the direction the induced current must flow to create a field that opposes that change. If flux is increasing into the page, the induced current creates a field out of the page inside the coil — use the right-hand grip rule to find the current direction around the coil.

The energy conservation argument is worth holding onto. When you push a magnet into a coil, you feel a resistive force — the induced current creates a magnetic field that repels the incoming magnet. You do work against that force, and that work is the source of the electrical energy delivered to the circuit. If the induced current instead attracted the magnet, it would accelerate indefinitely and generate unlimited energy, violating conservation of energy.

5. Connecting the Two Laws: The Negative Sign and What It Means

The full statement of Faraday's law, $\varepsilon = -\frac{\Delta(N\Phi)}{\Delta t}$, carries both laws simultaneously. The magnitude of the right-hand side gives you the size of the EMF (Faraday); the negative sign tells you the EMF acts to oppose the flux change (Lenz). In most AQA calculations you work with magnitudes and state the direction separately using Lenz's law reasoning — but recognising that the negative sign is not a mathematical accident is important for higher-mark explanation questions.

A useful way to think about it: the induced EMF drives a current that tries to maintain the status quo. Flux increasing? The induced current fights the increase. Flux decreasing? The induced current fights the decrease. The coil is, in effect, magnetically conservative — it resists change, much like inertia resists changes in motion.

6. Required Practical: Investigating Electromagnetic Induction

The standard AQA investigation uses a magnet, a coil, and a data logger or galvanometer to test Faraday's law quantitatively. The practical links directly to both spec requirements: you observe the phenomena and then use the data to verify the proportionality between induced EMF and rate of flux change.

One reliability point worth noting: the data logger captures the full EMF–time trace as the magnet passes through. You will see a positive peak as the magnet enters and a negative peak as it exits. The area under each peak is proportional to the total change in flux linkage — a neat graphical check of Faraday's law that examiners sometimes ask about.

7. Exam Technique and Common Mistakes

The most reliable way to lose marks on induction questions is to confuse flux with flux linkage, or to state Lenz's law without explaining the energy conservation reasoning behind it. The guidance below targets the patterns that appear most often in AQA mark schemes.

For 6-mark extended response questions on induction, the mark scheme typically rewards: a clear statement of Faraday's law with correct terminology; a statement of Lenz's law with the energy conservation justification; application to the specific scenario described; and a conclusion that ties the physics to the observable outcome. Practise structuring your answer in that order.

Frequently asked questions

What is Faraday's law?

Faraday's law of electromagnetic induction states that the induced EMF equals the rate of change of flux linkage: ε = -Δ(NΦ)/Δt. The magnitude gives the size of the EMF, and the negative sign expresses Lenz's law. The gradient of a flux linkage-time graph gives the induced EMF, so a flat section means zero EMF.

How do you predict the direction of an induced current?

First decide whether the flux through the coil is increasing or decreasing, then find the current direction that would create a field opposing that change. If flux into the page is increasing, the induced current creates a field out of the page inside the coil, and the right-hand grip rule then gives the direction of the current around the coil.

What is Lenz's law?

Lenz's law states that the induced current flows in a direction such that its magnetic effect opposes the change in flux that produced it. It is a consequence of conservation of energy: when a magnet is pushed into a coil, the induced current repels it, so work must be done, and that work is the source of the electrical energy delivered.

What happens when a magnet is pushed into a coil?

Pushing a magnet into a coil connected to a galvanometer makes the needle deflect, because the flux linkage through the coil is increasing. Pulling it out deflects the needle the opposite way, and holding it stationary gives a zero reading because the flux linkage is constant. Moving it faster, or using more turns, gives a larger deflection.

What does the EMF-time graph show when a magnet passes through a coil?

When a magnet passes through a coil, a data logger shows a positive EMF peak as the magnet enters and a negative peak as it exits. The area under each peak is proportional to the total change in flux linkage, which gives a neat graphical check of Faraday's law.

How do you calculate induced emf from a changing magnetic field?

Induced EMF from a changing field is |ε| = NΔΦ/Δt with ΔΦ = ΔB × A. A 200-turn coil of area 4.0 × 10⁻⁴ m² in a field rising from 0.10 T to 0.55 T in 0.030 s has ΔΦ = 1.8 × 10⁻⁴ Wb, so |ε| = 200 × 1.8 × 10⁻⁴ ÷ 0.030 = 1.2 V.

Why is there no current when a magnet is stationary in a coil?

A magnet held stationary inside a coil induces no current because the flux linkage through the coil is constant. An EMF is only induced when the flux linkage changes, whether because the magnet moves, the coil moves or the field strength changes.

How do more turns affect the induced emf?

More turns on a coil give a larger induced EMF for the same magnet speed, because each turn contributes its own flux, so the flux linkage NΦ is greater. Doubling the number of turns doubles the flux linkage and doubles the induced EMF for the same rate of change.

Why does Lenz's law obey conservation of energy?

Lenz's law is a direct consequence of conservation of energy: if the induced current aided the change in flux, it would create energy from nothing. Pushing a magnet into a coil meets a resistive force from the induced current's field, and the work done against that force is the source of the electrical energy delivered.

What does the gradient of a flux linkage–time graph show?

The gradient of a flux linkage–time graph gives the induced EMF. A steep gradient means a large EMF, and a flat section, where the flux linkage is constant, means zero EMF.

Why is there a negative sign in Faraday's law?

The negative sign in Faraday's law, ε = −Δ(NΦ)/Δt, is the mathematical expression of Lenz's law: the induced EMF acts to oppose the change in flux that produced it. Calculations usually work with magnitudes, with the direction stated separately using Lenz's law reasoning.

What happens if a magnet is moved into a coil faster?

Moving a magnet into a coil faster gives a larger galvanometer deflection, because the rate of change of flux linkage is greater, and the induced EMF equals that rate of change. Pushing in the S pole instead of the N pole reverses the direction of the deflection.

This CourseAll Revision NotesPast PapersPricing