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Writing Ionic Equations for Displacement Reactions Revision Notes | GCSE AQA Higher Chemistry

To write an ionic equation, split aqueous ionic compounds into ions, then remove the spectator ions that are unchanged. Free notes and 11 questions answered.

Updated 19 Mar 2026 · Revise Right Team

Writing Ionic Equations for Displacement Reactions is part of Reactivity of metals in GCSE AQA Higher Chemistry.

4 min

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24

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GCSE AQA Higher

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Reviewed by Revise Right

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What this lesson covers

To write an ionic equation, split aqueous ionic compounds into ions, then remove the spectator ions that are unchanged. Free notes and 11 questions answered.

  • Write ionic equations for displacement reactions involving metals
  • Identify spectator ions and remove them from full chemical equations
  • Apply the reactivity series to predict displacement reactions
  • Balance ionic equations correctly with appropriate state symbols

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Key ideas to keep in view

Use this lesson to stay inside Reactivity of metals while connecting the detail back to the wider Topic 4: Chemical changes topic.

  • Topic 4: Chemical changes
  • Reactivity of metals
  • GCSE AQA Higher Chemistry

Revision notes

Read the core explanations from Writing Ionic Equations for Displacement Reactions before testing yourself from memory.

1. Why Ionic Equations Matter

When zinc metal displaces copper from copper sulphate solution, something fascinating happens. The full equation shows lots of ions floating around, but only some actually do the work. Ionic equations strip away the noise and show you exactly what's happening at the atomic level.

This isn't just academic - it's how chemists understand reactions in batteries, metal extraction, and corrosion. You'll see this technique throughout A-level and beyond.

2. The Building Blocks

Think of it like a queue for a popular restaurant. If someone more important arrives, they can push in front of someone less important. In chemistry, 'importance' is determined by the reactivity series.

Picture a football match where some players are actively involved in the action, while others just watch from the sidelines. Spectator ions are the watchers - they're there, but they don't affect the outcome.

3. From Full Equations to Ionic Equations

Let's watch the transformation happen step by step. We'll start with a full equation and strip it down to show only what matters.

Worked example: Converting a Full Equation to an Ionic Equation

Convert this displacement reaction to an ionic equation: Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s)

  1. Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s) — This shows everything present in the reaction mixture
  2. Zn(s) + Cu²⁺(aq) + SO₄²⁻(aq) → Zn²⁺(aq) + SO₄²⁻(aq) + Cu(s) — Only split compounds marked (aq) - solids stay as they are
  3. SO₄²⁻ appears on both sides unchanged — Spectator ions don't participate - they're just along for the ride
  4. Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s) — This is the ionic equation - it shows only the active participants

Answer: Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)

Notice how much cleaner this looks. The ionic equation tells the real story: zinc atoms give up electrons to become Zn²⁺ ions, while Cu²⁺ ions grab those electrons to become copper atoms.

4. The Reactivity Series Connection

Not every metal can displace every other metal. The reactivity series is your guide - it tells you who can push out whom.

Reactivity Series (most to least reactive):Potassium > Sodium > Lithium > Calcium > Magnesium > Aluminium > Carbon > Zinc > Iron > Tin > Lead > Hydrogen > Copper > Silver > Gold

The rule is simple: metals higher up can displace metals lower down from their compounds. Zinc can displace copper because zinc is higher in the series.

Worked example: Predicting and Writing Ionic Equations

Will magnesium displace silver from silver nitrate solution? If yes, write the ionic equation.

  1. Magnesium is above silver in the reactivity series — Mg can displace Ag because Mg is more reactive
  2. Mg(s) + 2AgNO₃(aq) → Mg(NO₃)₂(aq) + 2Ag(s) — Balance the equation - need 2 Ag atoms to balance charges
  3. Mg(s) + 2Ag⁺(aq) + 2NO₃⁻(aq) → Mg²⁺(aq) + 2NO₃⁻(aq) + 2Ag(s) — Split the aqueous compounds into their ions
  4. Mg(s) + 2Ag⁺(aq) → Mg²⁺(aq) + 2Ag(s) — NO₃⁻ ions are spectators - remove them to get the ionic equation

Answer: Mg(s) + 2Ag⁺(aq) → Mg²⁺(aq) + 2Ag(s)

5. Common Patterns and Mistakes

Most displacement reactions follow the same pattern. Once you recognise it, writing ionic equations becomes straightforward.

The Universal Pattern:More reactive metal + Metal ion → Metal ion + Less reactive metal

The key is identifying which ions are doing the actual work and which are just spectating. Anions like SO₄²⁻, NO₃⁻, and Cl⁻ are usually spectators in displacement reactions.

Trap Alert: Many students forget to balance ionic equations. Remember, Fe³⁺ needs 3 electrons, so you might need 3 atoms of the displacing metal to balance the charges.

6. Exam Success Strategy

Examiners love testing ionic equations because they reveal whether you truly understand what's happening in reactions. Here's how to nail these questions every time.

Command Word Decoder:

'Write the ionic equation' - Remove spectator ions and balance the equation. Always include state symbols.

'Explain why no reaction occurs' - Check the reactivity series. If the metal is trying to displace something more reactive, no reaction happens.

'Identify the spectator ions' - Look for ions that appear unchanged on both sides of the full equation.

Mark-Winning Strategy: Always work systematically. Write the full equation first, then identify and remove spectators. This prevents careless errors and shows clear working for method marks.

Exam precision note: In Writing Ionic Equations for Displacement Reactions - Oxidation and reduction in terms of electrons (HT only) - Reactivity of metals, always identify the key chemical idea first, then link it to evidence, data, or an equation. A high-scoring GCSE answer names the particles involved, states what changes, and justifies the conclusion using correct scientific language. Where calculations are used, show each step with units and keep significant figures sensible. Finally, check that terminology matches AQA wording so your answer is unambiguous and mark-scheme friendly.

For AQA Higher Tier, ionic equations for displacement reactions should show which ions are oxidised and which ions are reduced. Removing spectator ions helps you focus on the species that actually change during the reaction, which makes the electron transfer clearer.

Frequently asked questions

How do you write an ionic equation?

To write an ionic equation, write the full balanced equation, split the aqueous ionic compounds into ions, then remove the spectator ions that appear unchanged on both sides. For Zn + CuSO₄ → ZnSO₄ + Cu, removing SO₄²⁻ gives Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s).

What are spectator ions?

Spectator ions are ions that are present in a reaction mixture but do not take part in the actual reaction, so they remain unchanged. In displacement reactions, anions such as SO₄²⁻, NO₃⁻ and Cl⁻ are usually spectators.

How do you balance an ionic equation?

An ionic equation is balanced so that atoms and charges match on both sides. Mg(s) + 2Ag⁺(aq) → Mg²⁺(aq) + 2Ag(s) needs 2 Ag to balance the charges, and Fe³⁺ needs 3 electrons, so more atoms of the displacing metal may be needed.

What is the ionic equation for magnesium and silver nitrate?

The ionic equation for magnesium displacing silver from silver nitrate is Mg(s) + 2Ag⁺(aq) → Mg²⁺(aq) + 2Ag(s). The nitrate ions are spectators, and 2 silver ions are needed to balance the charge of one Mg²⁺ ion.

Why can't some metals displace others?

A metal cannot displace a more reactive metal from its compound, so no reaction happens. Metals higher in the reactivity series displace metals lower down; for example, zinc displaces copper because zinc is higher in the series.

Why are ionic equations useful?

Ionic equations are useful because they remove spectator ions and show only the species that actually change, which makes the electron transfer clearer. In Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s), zinc atoms give up electrons and Cu²⁺ ions gain them.

What is the ionic equation for zinc and copper sulfate?

The ionic equation for zinc and copper sulphate is Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s). The SO₄²⁻ ions are spectator ions, so they are removed. Zinc atoms give up electrons to become Zn²⁺ ions, while Cu²⁺ ions grab those electrons to become copper atoms.

Which ions are usually spectator ions?

Anions such as SO₄²⁻, NO₃⁻ and Cl⁻ are usually spectator ions in displacement reactions. They appear unchanged on both sides of the full equation because they don't take part in the actual reaction, so they are left out of the ionic equation.

Which compounds are split into ions in an ionic equation?

Only compounds marked (aq) are split into ions when writing an ionic equation; solids stay as they are. For Zn(s) + CuSO₄(aq), only CuSO₄ and ZnSO₄ are split, giving Cu²⁺, Zn²⁺ and SO₄²⁻ ions.

Do ionic equations need state symbols?

Ionic equations should always include state symbols. The ionic equation for magnesium and silver nitrate, for example, is Mg(s) + 2Ag⁺(aq) → Mg²⁺(aq) + 2Ag(s).

What is the general pattern for displacement ionic equations?

Most displacement reactions follow the pattern: more reactive metal + metal ion → metal ion + less reactive metal. The more reactive metal loses electrons and is oxidised, while the metal ion gains electrons and is reduced.

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