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Testing for Halide Ions with Silver Nitrate Revision Notes | GCSE AQA Higher Chemistry

Add dilute nitric acid then silver nitrate: chloride gives a white precipitate, bromide cream and iodide yellow. Free notes and 9 questions answered.

Updated 19 Mar 2026 · Revise Right Team

Testing for Halide Ions with Silver Nitrate is part of Identification of ions by chemical and spectroscopic means (chemistry only) in GCSE AQA Higher Chemistry.

3 min

Reading time

17

Lessons in this topic

GCSE AQA Higher

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What this lesson covers

Add dilute nitric acid then silver nitrate: chloride gives a white precipitate, bromide cream and iodide yellow. Free notes and 9 questions answered.

  • Describe the test for halide ions using silver nitrate solution
  • Explain why dilute nitric acid is added before the silver nitrate test
  • Identify chloride, bromide and iodide ions from their precipitate colours
  • Apply the halide test to unknown solutions in exam questions

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Key ideas to keep in view

Use this lesson to stay inside Identification of ions by chemical and spectroscopic means (chemistry only) while connecting the detail back to the wider Topic 8: Chemical analysis topic.

  • Topic 8: Chemical analysis
  • Identification of ions by chemical and spectroscopic means (chemistry only)
  • GCSE AQA Higher Chemistry

Revision notes

Read the core explanations from Testing for Halide Ions with Silver Nitrate before testing yourself from memory.

1. Why Test for Halide Ions?

Imagine you're a forensic scientist analysing a water sample from a crime scene. You need to know exactly which ions are present. Halide ions (chloride, bromide, iodide) are common in nature and industry, so identifying them accurately is crucial.

The silver nitrate test is your go-to method. It's quick, reliable, and gives you a clear visual result. Each halide ion produces a different coloured precipitate when it meets silver ions.

2. The Silver Nitrate Test Method

Here's the key insight: silver ions (Ag⁺) react with halide ions to form insoluble silver halides. Each silver halide has a distinctive colour, making identification straightforward.

Worked example: Required Practical: Testing for Halide Ions

Test an unknown solution to identify which halide ion it contains.

  1. Add 2-3 drops of dilute HNO₃ to the test solution — This removes carbonate ions that would interfere with the test
  2. Add 2-3 drops of AgNO₃(aq) to the acidified solution — Silver ions will react with any halide ions present
  3. Note the colour of any precipitate formed — White = chloride, cream = bromide, yellow = iodide
  4. Identify the halide ion based on precipitate colour — Always state which specific ion is present, not just the colour

Answer: The halide ion present depends on the precipitate colour observed

**Trap**: Many students forget the nitric acid step. Without it, carbonate ions can also form a precipitate with silver nitrate, so acidifying first helps remove carbonate ions before testing for halides.

3. The Chemical Reactions

Each halide ion reacts with silver nitrate to form a different silver halide precipitate. The reactions are straightforward ionic equations.

Notice the pattern: all three reactions follow the same format. One silver ion combines with one halide ion to form an insoluble silver halide. The only difference is the colour of the precipitate formed.

4. Colour Memory Tricks

The precipitate colours are the heart of this test. You need to memorise them perfectly because exam questions often show you a colour and ask you to identify the ion.

Here's a memory trick that works: **White Cream Yellow** matches the alphabetical order **Chloride Bromide Iodide**. Also think about intensity - white is lightest, yellow is darkest, cream is in between.

5. Common Exam Scenarios

Exam questions love to test this practical in different ways. You might get a table to complete, a method to evaluate, or results to interpret. Let's tackle the most common question types.

Worked example: Interpreting Test Results

A student tests three unknown solutions A, B and C. Solution A gives a white precipitate, B gives a cream precipitate, and C gives a yellow precipitate. Identify the halide ions present. [3 marks]

  1. White precipitate = AgCl formed — Therefore solution A contains Cl⁻ ions [1 mark]
  2. Cream precipitate = AgBr formed — Therefore solution B contains Br⁻ ions [1 mark]
  3. Yellow precipitate = AgI formed — Therefore solution C contains I⁻ ions [1 mark]

Answer: A contains chloride ions, B contains bromide ions, C contains iodide ions

**Trap**: Students often write the precipitate name instead of the ion. The question asks for the halide ion present, so write Cl⁻, Br⁻, or I⁻, not AgCl, AgBr, or AgI.

6. Exam Technique and Mark Winners

This test appears regularly in AQA papers, often worth 3-6 marks. The marking is predictable once you know the patterns examiners look for.

**Mark-winning language**: 'Add dilute nitric acid followed by silver nitrate solution. A white precipitate indicates chloride ions.' This gets full marks because it includes the method, observation, and conclusion.

Exam precision note: In Testing for Halide Ions with Silver Nitrate - Halides - Identification of ions by chemical and spectroscopic means (chemistry only), always identify the key chemical idea first, then link it to evidence, data, or an equation. A high-scoring GCSE answer names the particles involved, states what changes, and justifies the conclusion using correct scientific language. Where calculations are used, show each step with units and keep significant figures sensible. Finally, check that terminology matches AQA wording so your answer is unambiguous and mark-scheme friendly.

The solution is acidified with dilute nitric acid before adding silver nitrate so that carbonate ions are removed first and do not interfere with the result. A white precipitate suggests chloride, cream suggests bromide, and yellow suggests iodide.

Frequently asked questions

What are halide ions?

Halide ions are negative ions formed when Group 7 elements (halogens) gain one electron. The three tested with silver nitrate are chloride (Cl⁻), bromide (Br⁻) and iodide (I⁻).

How do you test for halide ions?

To test for halide ions, add dilute nitric acid to the solution, then add silver nitrate solution. A white precipitate shows chloride, a cream precipitate shows bromide and a yellow precipitate shows iodide.

What colour is silver chloride?

Silver chloride is a white precipitate, silver bromide is cream and silver iodide is yellow. The colours get darker going down Group 7, so the colour shows which halide ion is present.

What colour is silver iodide?

Silver iodide is a yellow precipitate. It forms when silver nitrate is added to a solution containing iodide ions (I⁻), after acidifying with dilute nitric acid.

What colour is silver bromide?

Silver bromide is a cream precipitate. It forms when silver nitrate is added to a solution containing bromide ions (Br⁻), after acidifying with dilute nitric acid.

How do silver ions react with chloride ions?

One silver ion combines with one chloride ion to form insoluble silver chloride: Ag⁺ + Cl⁻ → AgCl, a white precipitate. Bromide and iodide ions react in the same way, forming cream AgBr and yellow AgI.

Why is nitric acid added before silver nitrate?

Dilute nitric acid is added first to remove carbonate ions, because without it carbonate ions can also form a precipitate with silver nitrate and interfere with the test for halide ions.

What should you write as the answer to a halide test question?

In a halide test question, write the halide ion present, such as Cl⁻, Br⁻ or I⁻, not the precipitate formed, such as AgCl, AgBr or AgI. For example, a white precipitate means the solution contains chloride ions.

How do you remember the halide precipitate colours?

The halide precipitate colours are white, cream, yellow, matching chloride, bromide, iodide in alphabetical order. The colours get darker going down Group 7, with white the lightest and yellow the darkest.

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