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Limits of Accuracy and Upper and Lower Bounds Revision Notes | GCSE AQA Higher Maths

To find upper and lower bounds, halve the degree of accuracy, then subtract it for the lower bound and add it for the upper. 12 questions answered.

Updated 21 Mar 2026 · Revise Right Team

Limits of Accuracy and Upper and Lower Bounds is part of Measures and accuracy in GCSE AQA Higher Maths.

4 min

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22

Lessons in this topic

GCSE AQA Higher

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Reviewed by Revise Right

Content review

What this lesson covers

To find upper and lower bounds, halve the degree of accuracy, then subtract it for the lower bound and add it for the upper. 12 questions answered.

  • Apply limits of accuracy to measurements rounded to a given degree of accuracy
  • Calculate the upper and lower bounds of a measurement
  • Find upper and lower bounds of expressions involving multiple measurements
  • Interpret bounds in context to give sensible answers to problems

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Key ideas to keep in view

Use this lesson to stay inside Measures and accuracy while connecting the detail back to the wider Number topic.

  • Lower bound: The smallest value a measurement could take and still round to the given value. Found by subtracting half the degree of accuracy from the rounded value.
  • Upper bound: The largest value a measurement could take and still round to the given value. Found by adding half the degree of accuracy to the rounded value.
  • Limits of accuracy: The range of values within which a true measurement must lie, expressed as lower bound \leq x < upper bound.
  • Degree of accuracy: The precision to which a measurement is given, for example to the nearest integer, nearest 10, or to 1 decimal place.

Revision notes

Read the core explanations from Limits of Accuracy and Upper and Lower Bounds before testing yourself from memory.

1. Why Measurements Are Never Exact

Every measurement you read in a maths problem has been rounded. A length of 8 cm could actually be anywhere from 7.5 cm up to (but not including) 8.5 cm — both round to 8 cm to the nearest centimetre. This raises a real question: if you use that measurement in a calculation, how wrong could your answer be?

That is exactly what limits of accuracy and upper and lower bounds let you answer. Rather than pretending a measurement is exact, you work out the worst-case and best-case values — and that tells you how much you can trust your result.

2. Upper and Lower Bounds — The Core Idea

When a value has been rounded, there is a range of original values that could have produced it. The lower bound is the smallest value in that range, and the upper bound is the largest. Together they define the limits of accuracy.

The inequality is strict at the upper end ($<$ not $\leq$) because a value exactly at the upper bound would round up to the next value, not to $x$. This is a detail examiners test directly, so it is worth locking in now.

3. Worked Examples — Finding Bounds

The method is the same regardless of the degree of accuracy — identify what the rounding unit is, halve it, then add and subtract. Here are two contrasting examples to build fluency.

Worked example: Finding Bounds: Rounded to the Nearest Integer

A plank of wood is measured as 12 m, rounded to the nearest metre. Find the upper and lower bounds of its length.

  1. Rounded to the nearest metre, so degree of accuracy $= 1$ m — The degree of accuracy is the unit being rounded to. Here it is 1 metre. [M1]
  2. $\dfrac{1}{2} = 0.5$ m — This is the amount we add and subtract to find the bounds.
  3. $\text{LB} = 12 - 0.5 = 11.5$ m — The smallest value that rounds to 12 m. [A1]
  4. $\text{UB} = 12 + 0.5 = 12.5$ m — The largest value that rounds to 12 m (not included). [A1]
  5. $11.5 \leq x < 12.5$ — Closed inequality at 11.5, open at 12.5. This is the standard exam notation.

Answer: Lower bound = 11.5 m, Upper bound = 12.5 m. Limits: $11.5 \leq x < 12.5$

Worked example: Finding Bounds: Rounded to 1 Decimal Place

A mass is recorded as 4.6 kg, rounded to 1 decimal place. Find the upper and lower bounds.

  1. Rounded to 1 decimal place, so degree of accuracy $= 0.1$ kg — 1 decimal place means the rounding unit is 0.1. [M1]
  2. $\dfrac{0.1}{2} = 0.05$ kg — We add and subtract 0.05 to find the bounds.
  3. $\text{LB} = 4.6 - 0.05 = 4.55$ kg — Any mass from 4.55 kg upwards rounds to 4.6 kg. [A1]
  4. $\text{UB} = 4.6 + 0.05 = 4.65$ kg — A mass of exactly 4.65 kg would round to 4.7 kg, so 4.65 is not included. [A1]
  5. $4.55 \leq x < 4.65$ — Standard inequality notation for the limits of accuracy.

Answer: Lower bound = 4.55 kg, Upper bound = 4.65 kg. Limits: $4.55 \leq x < 4.65$

4. Bounds in Calculations — The Critical Step

Finding bounds for a single measurement is the foundation. The real exam challenge is combining bounds from two or more measurements in a calculation. The rule here is not obvious, and it is where most marks are dropped.

The key principle: to get the upper bound of the result, you must combine the bounds of each measurement in the way that makes the result as large as possible. To get the lower bound of the result, combine them to make the result as small as possible.

OperationUpper bound of resultLower bound of result
$A + B$$\text{UB}(A) + \text{UB}(B)$$\text{LB}(A) + \text{LB}(B)$
$A - B$$\text{UB}(A) - \text{LB}(B)$$\text{LB}(A) - \text{UB}(B)$
$A \times B$$\text{UB}(A) \times \text{UB}(B)$$\text{LB}(A) \times \text{LB}(B)$
$A \div B$$\text{UB}(A) \div \text{LB}(B)$$\text{LB}(A) \div \text{UB}(B)$

The subtraction and division rows are the ones that trip students up. For subtraction, the upper bound of the result uses the lower bound of the quantity being subtracted — because subtracting less gives a larger answer. For division, dividing by a smaller number gives a larger result, so the upper bound uses the lower bound of the divisor.

Worked example: Upper and Lower Bounds of an Area

A rectangle has length $L = 9$ cm and width $W = 4$ cm, both rounded to the nearest centimetre. Calculate the upper bound and lower bound of the area. Give your answers to 2 decimal places where necessary.

  1. $\text{LB}(L) = 9 - 0.5 = 8.5$ cm $\text{UB}(L) = 9 + 0.5 = 9.5$ cm — Degree of accuracy is 1 cm, so halve to get 0.5 cm. [M1]
  2. $\text{LB}(W) = 4 - 0.5 = 3.5$ cm $\text{UB}(W) = 4 + 0.5 = 4.5$ cm — Same degree of accuracy applies to the width.
  3. $\text{UB}(\text{Area}) = \text{UB}(L) \times \text{UB}(W) = 9.5 \times 4.5$ $= 42.75 \text{ cm}^2$ — Multiply the two largest possible values: $9.5 \times 4.5 = 9.5 \times 4 + 9.5 \times 0.5 = 38 + 4.75 = 42.75$. [A1]
  4. $\text{LB}(\text{Area}) = \text{LB}(L) \times \text{LB}(W) = 8.5 \times 3.5$ $= 29.75 \text{ cm}^2$ — Multiply the two smallest possible values: $8.5 \times 3.5 = 8.5 \times 3 + 8.5 \times 0.5 = 25.5 + 4.25 = 29.75$. [A1]
  5. Upper bound of area $= 42.75 \text{ cm}^2$ Lower bound of area $= 29.75 \text{ cm}^2$ — Always state which bound is which and include units. Missing units costs a mark.

Answer: Upper bound of area = 42.75 cm², Lower bound of area = 29.75 cm²

Worked example: Upper and Lower Bounds of a Division (Speed Calculation)

Mohammed runs a distance of $d = 100$ m, rounded to the nearest metre, in a time of $t = 12$ s, rounded to the nearest second. Calculate the upper bound of his speed. Give your answer to 3 significant figures.

  1. $\text{LB}(d) = 100 - 0.5 = 99.5$ m $\text{UB}(d) = 100 + 0.5 = 100.5$ m — Degree of accuracy is 1 m. [M1]
  2. $\text{LB}(t) = 12 - 0.5 = 11.5$ s $\text{UB}(t) = 12 + 0.5 = 12.5$ s — Degree of accuracy is 1 s.
  3. $\text{Speed} = \dfrac{d}{t}$ Upper bound of speed $= \dfrac{\text{UB}(d)}{\text{LB}(t)}$ — To maximise a fraction, use the largest numerator and smallest denominator. Dividing by a smaller number gives a larger result. [M1]
  4. $\text{UB(speed)} = \dfrac{100.5}{11.5} = 8.739\ldots$ m/s — $100.5 \div 11.5$: $11.5 \times 8 = 92$, remainder $8.5$; $8.5 \div 11.5 \approx 0.739$. So $\approx 8.739$ m/s. [A1]
  5. $8.739\ldots \approx 8.74$ m/s (3 s.f.) — The fourth significant figure is 9, so round up. Always round only at the final step.

Answer: Upper bound of speed = 8.74 m/s (3 s.f.)

5. Interpreting Bounds in Context

Sometimes an exam question asks you to use bounds to make a decision or give a sensible answer. This is where you apply and interpret the limits of accuracy rather than just calculate them.

A typical question might ask: "Can you be certain that the total length exceeds 20 m?" To answer this, you check the lower bound of the total. If the lower bound is greater than 20 m, then yes — even in the worst case, the total exceeds 20 m. If the lower bound is less than or equal to 20 m, you cannot be certain.

Worked example: Interpreting Bounds to Make a Decision

Two planks have lengths $A = 3.2$ m and $B = 2.9$ m, both rounded to 1 decimal place. Aisha needs a combined length of at least 6 m. Can she be certain the planks are long enough?

  1. $\text{LB}(A) = 3.2 - 0.05 = 3.15$ m — Degree of accuracy is 0.1 m, so halve to get 0.05 m. [M1]
  2. $\text{LB}(B) = 2.9 - 0.05 = 2.85$ m — Same degree of accuracy.
  3. $\text{LB}(A + B) = \text{LB}(A) + \text{LB}(B) = 3.15 + 2.85 = 6.00$ m — For a sum, the lower bound uses both lower bounds. [A1]
  4. Lower bound $= 6.00$ m, which is exactly 6 m. — The lower bound equals exactly 6 m, which means the true value is ≥ 6.00 m, meeting the requirement. If asked if it strictly exceeds 6 m, Aisha cannot be certain.

Answer: Aisha can be certain the total is ≥ 6.00 m. However, she cannot be certain it strictly exceeds 6 m since the lower bound is exactly 6.00 m.

6. Deliberate Practice

These problems cover the full range of bound types you will meet in an Higher-tier exam. Work through each one before checking the solution.

7. Exam Technique and Common Mistakes

You now have the method. This section focuses on the specific errors that cost marks in GCSE Higher exam questions on this topic. Remember to include a teaching or transition between blocks to reinforce learning.

Frequently asked questions

How do you find upper and lower bounds?

To find upper and lower bounds, halve the degree of accuracy, then subtract it for the lower bound and add it for the upper bound. A plank measured as 12 m to the nearest metre has a lower bound of 11.5 m and an upper bound of 12.5 m.

What are limits of accuracy?

Limits of accuracy are the lower and upper bounds of a rounded value, the smallest and largest values that could round to it. If x is rounded to a degree of accuracy d, the lower bound is x - d/2 and the upper bound is x + d/2.

What is a suitable degree of accuracy for a bounds answer?

The right degree of accuracy for a bounds answer is the one the question asks for, such as 3 significant figures, and rounding should happen only at the final step. For example, 100.5 ÷ 11.5 = 8.739... is given as 8.74 m/s to 3 significant figures.

What is the formula for upper and lower bounds?

For a value x rounded to a degree of accuracy d, the lower bound is x - d/2 and the upper bound is x + d/2. The true value satisfies lower bound ≤ true value < upper bound.

What are the rules for limits of accuracy in calculations?

The limits of accuracy rules say the upper bound of A + B is UB(A) + UB(B), of A - B is UB(A) - LB(B), of A × B is UB(A) × UB(B), and of A ÷ B is UB(A) ÷ LB(B). The lower bounds are LB(A) + LB(B), LB(A) - UB(B), LB(A) × LB(B) and LB(A) ÷ UB(B).

How do you find the upper bound when subtracting or dividing?

The upper bound of A - B is UB(A) - LB(B), because subtracting less gives a larger answer, and the lower bound is LB(A) - UB(B). For division, the upper bound of A ÷ B is UB(A) ÷ LB(B), because dividing by a smaller number gives a larger result.

Why is the upper bound not included?

The upper bound is not included because a value exactly at the upper bound would round up to the next value. For example, a mass of exactly 4.65 kg would round to 4.7 kg, so the limits for 4.6 kg run from 4.55 kg up to, but not including, 4.65 kg.

How do you use bounds to make a decision?

To decide whether a result is certain, check the worst case using the bounds. Two planks of 3.2 m and 2.9 m, both to 1 d.p., have a lower bound total of 3.15 + 2.85 = 6.00 m, so they are certainly at least 6 m long, but not certainly more than 6 m.

What is a limit of accuracy in maths?

A limit of accuracy is one end of the range of original values that could have produced a rounded measurement: the lower bound or the upper bound. A length of 8 cm to the nearest centimetre could be anywhere from 7.5 cm up to, but not including, 8.5 cm.

What are the bounds of 4.6 kg to 1 decimal place?

The bounds of 4.6 kg to 1 decimal place are 4.55 kg and 4.65 kg, so 4.55 ≤ x < 4.65. The degree of accuracy is 0.1 kg, so 0.05 kg is subtracted and added, and 4.65 is not included because it would round to 4.7.

How do you find the lower bound of a subtraction?

The lower bound of a subtraction A - B is LB(A) - UB(B): the smallest possible first value minus the largest possible second value. Subtracting more gives a smaller answer, which is why the upper bound of B is used.

How do you find the upper bound of a sum?

The upper bound of a sum A + B is UB(A) + UB(B), and the lower bound is LB(A) + LB(B). For planks of 3.2 m and 2.9 m to 1 decimal place, the lower bound of the total is 3.15 + 2.85 = 6.00 m.

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