The conservation of momentum equation is m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂, where u represents initial velocities and v represents final velocities. Free notes.
Updated 20 Mar 2026 · Revise Right Team
Momentum Calculations is part of Momentum (HT only) in GCSE AQA Higher Physics.
4 min
Reading time
39
Lessons in this topic
GCSE AQA Higher
Pathway
Reviewed by Revise Right
Content review
What this lesson covers
The conservation of momentum equation is m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂, where u represents initial velocities and v represents final velocities. Free notes.
Calculate momentum using the equation p = mv and rearrange to find mass or velocity
Apply conservation of momentum to collision problems involving two objects
Explain how momentum is conserved in isolated systems during collisions
Evaluate the momentum changes in real-world collision scenarios
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Use this lesson to stay inside Momentum (HT only) while connecting the detail back to the wider Forces topic.
Forces
Momentum (HT only)
GCSE AQA Higher Physics
Revision notes
Read the core explanations from Momentum Calculations before testing yourself from memory.
1. What is Momentum?
Picture a massive lorry and a small car both travelling at 30 mph. Which would be harder to stop? Your instinct says the lorry - and physics agrees. The lorry has more momentum.
Momentum captures this idea perfectly. It combines both mass and velocity into one quantity that tells us how much 'oomph' a moving object has. A heavy object moving slowly can have the same momentum as a light object moving fast.
2. The Momentum Equation
The momentum equation is beautifully simple, but don't let that fool you. It's one of the most powerful tools in physics.
Notice that momentum is a vector quantity - it has both magnitude and direction. If two identical cars travel at the same speed but in opposite directions, their momenta cancel out when added together.
You can rearrange this equation to find any unknown quantity. Need to find mass? Use $m = \frac{p}{v}$. Need velocity? Use $v = \frac{p}{m}$.
Worked example: Calculating Momentum
A 1200 kg car travels at 25 m/s. Calculate its momentum. [2 marks]
$p = mv$ — [M1] for correct formula
$p = 1200 \times 25$ — Mass in kg, velocity in m/s
$p = 30,000$ kg m/s — [A1] for correct answer with units
Answer: 30,000 kg m/s
3. Conservation of Momentum
Here's where momentum gets really interesting. When objects collide, something remarkable happens - the total momentum stays exactly the same before and after the collision.
This works because of Newton's third law. When object A pushes on object B during a collision, object B pushes back with an equal and opposite force. The momentum lost by A exactly equals the momentum gained by B.
The conservation equation looks like this: momentum before = momentum after, or $m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2$, where u represents initial velocities and v represents final velocities.
4. Collision Calculations
Real collision problems can look intimidating, but there's a systematic approach that works every time. The key is to be methodical about directions and signs.
Choose a positive direction (usually right or the direction of initial motion). Any object moving in this direction has positive velocity; any object moving opposite has negative velocity.
Worked example: Two-Object Collision
A 3 kg trolley moving at 4 m/s collides with a stationary 2 kg trolley. After collision, the 3 kg trolley moves at 1 m/s in the same direction. Find the velocity of the 2 kg trolley. [4 marks]
$m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2$ — [M1] for conservation of momentum
$(3 \times 4) + (2 \times 0) = (3 \times 1) + (2 \times v_2)$ — Second trolley initially at rest, so $u_2 = 0$
$2v_2 = 12 - 3 = 9$
$v_2 = 4.5$ m/s — [A1] for correct final answer with units
Answer: 4.5 m/s in the positive direction
Notice how the momentum was redistributed. The 3 kg trolley slowed down from 4 m/s to 1 m/s, losing momentum. The 2 kg trolley gained exactly this amount, accelerating from rest to 4.5 m/s.
5. Real-World Applications
Momentum conservation isn't just a physics curiosity - it governs everything from car safety to space travel. Understanding it helps explain why certain safety features work and others don't.
Car crumple zones work by extending collision time. The momentum change is the same, but spreading it over longer time reduces the force ($F = \frac{\Delta p}{\Delta t}$). This is why modern cars are designed to deform in crashes.
Rockets work by conservation of momentum too. They throw hot gases backwards at high speed, and by Newton's third law, the rocket gains momentum forwards. No air is needed - rockets work perfectly in space.
Even walking relies on momentum conservation. You push backwards on the ground, and the ground pushes forwards on you. The Earth gains a tiny amount of momentum backwards, but its enormous mass means its velocity change is negligible.
6. Exam Technique and Common Mistakes
Momentum questions are mark-winners if you know the technique, but they're full of traps for the unwary. Here's how to avoid the common pitfalls and secure full marks.
Always define your positive direction clearly at the start. Write something like 'taking rightward as positive' so the examiner knows your sign convention. This prevents confusion with negative velocities.
Show every step of your working. Even if you make an arithmetic error, you can still get method marks for using the correct formula and approach. Never skip the formula step - it's usually worth a mark.
For 6-mark questions, structure your answer clearly: state the principle (conservation of momentum), write the equation, substitute values, solve algebraically, then calculate numerically. This methodical approach maximises your mark potential.
Sources and content standards
Published by Revise Right. Use the official specification reference to check the requirements for your course. Content updated: 2026-03-20.
The conservation of momentum equation is m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂, where u represents initial velocities and v represents final velocities. Total momentum before a collision equals total momentum after.
Why is momentum conserved in collisions?
Momentum is conserved because of Newton's third law: when object A pushes on object B, B pushes back with an equal and opposite force. The momentum lost by A exactly equals the momentum gained by B, so the total stays the same.
What is an isolated system?
An isolated system is one where total momentum before a collision equals total momentum after. This works because of Newton's third law: the momentum lost by one object exactly equals the momentum gained by the other.
How do you solve a momentum collision problem?
Choose a positive direction, then set total momentum before equal to total momentum after and solve. A 3 kg trolley at 4 m/s hits a stationary 2 kg trolley and slows to 1 m/s, so (3 × 4) + 0 = (3 × 1) + 2v, giving v = 4.5 m/s for the 2 kg trolley.
How do rockets use conservation of momentum?
Rockets throw hot gases backwards at high speed, and by conservation of momentum the rocket gains momentum forwards. No air is needed for the rocket to push against, so rockets work perfectly in space.
Does the Earth move when you walk?
When a person walks, they push backwards on the ground and the ground pushes forwards on them, so the Earth gains a tiny amount of momentum backwards. Its enormous mass means its velocity change is negligible.
Why do you need a sign convention in momentum questions?
A sign convention stops sign errors with velocities in opposite directions. Choose a positive direction, usually right or the direction of initial motion, write 'taking rightward as positive', and give objects moving the other way a negative velocity.
What is the velocity of a 2 kg trolley hit by a 3 kg trolley at 4 m/s?
A 3 kg trolley at 4 m/s hits a stationary 2 kg trolley and slows to 1 m/s, so the 2 kg trolley moves at 4.5 m/s. Using (3 × 4) + (2 × 0) = (3 × 1) + 2v₂, 12 = 3 + 2v₂, so v₂ = 4.5 m/s.
Do momenta in opposite directions cancel?
Two identical cars travelling at the same speed in opposite directions have momenta that cancel out when added together, because momentum is a vector with both magnitude and direction.
How do you find velocity from momentum?
Velocity is found from momentum by rearranging p = mv to v = p/m, momentum ÷ mass. To find mass instead, m = p/v, with momentum in kg m/s and velocity in m/s.
How should a 6-mark momentum question be structured?
A 6-mark momentum answer should state the principle (conservation of momentum), write the equation, substitute values, solve algebraically, then calculate numerically. A positive direction should be stated at the start, such as 'taking rightward as positive'.
How was momentum shared in the trolley collision?
In a collision, momentum is redistributed: a 3 kg trolley slowing from 4 m/s to 1 m/s loses 9 kg m/s, and a 2 kg trolley at rest gains exactly 9 kg m/s, so it moves at 4.5 m/s.
Why is a lorry harder to stop than a car at 30 mph?
A lorry has much more momentum than a small car when both travel at 30 mph, because of its larger mass. Momentum combines mass and velocity, so more momentum makes the lorry harder to stop.