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Systematic Enumeration Using Tables, Grids and Venn Diagrams Revision Notes | GCSE AQA Higher Maths

A sample space diagram is a two-way grid listing every outcome of two combined events, with one event across the top and the other down the side. Free notes.

Updated 21 Mar 2026 · Revise Right Team

Systematic Enumeration Using Tables, Grids and Venn Diagrams is part of Sample Spaces and Systematic Enumeration in GCSE AQA Higher Maths.

5 min

Reading time

12

Lessons in this topic

GCSE AQA Higher

Pathway

Reviewed by Revise Right

Content review

What this lesson covers

A sample space diagram is a two-way grid listing every outcome of two combined events, with one event across the top and the other down the side. Free notes.

  • Enumerate all possible outcomes of combined events systematically using tables and grids
  • Construct and interpret Venn diagrams to represent sets and combinations of sets
  • Use systematic enumeration to calculate probabilities from sample spaces
  • Identify intersections, unions, and complements of sets from Venn diagrams

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Key ideas to keep in view

Use this lesson to stay inside Sample Spaces and Systematic Enumeration while connecting the detail back to the wider Probability topic.

  • Sample space: The complete set of all possible outcomes of an experiment. Used when listing every outcome systematically to avoid missing any.
  • Venn diagram: A diagram using overlapping circles inside a rectangle to show how sets relate. Used when outcomes can belong to more than one category simultaneously.
  • Intersection: The set of outcomes belonging to two or more sets at the same time, written $A \cap B$. Used when identifying outcomes that satisfy multiple conditions.
  • Union: The set of all outcomes belonging to at least one of two sets, written $A \cup B$. Used when counting outcomes that satisfy one condition or another (or both).

Revision notes

Read the core explanations from Systematic Enumeration Using Tables, Grids and Venn Diagrams before testing yourself from memory.

1. Why Systematic Enumeration Matters

Imagine rolling two dice and trying to find the probability of getting a total of 7. If you list outcomes randomly, you will almost certainly miss some — and a missed outcome means a wrong probability. Systematic enumeration is the discipline of listing every possible outcome in a structured way so that nothing is overlooked.

the examiner expects you to use three specific tools for this: tables, grids, and Venn diagrams. Each tool suits a different type of problem, and knowing which to reach for is half the battle. This lesson builds all three skills from the ground up.

2. Tables and Grids for Combined Events

When two independent events each have a small number of outcomes, a sample space diagram (also called a possibility space or grid) is the most reliable enumeration tool. You place the outcomes of one event along the top and the outcomes of the other down the side, then fill every cell with the combined result.

The power of a grid is that its structure forces you to account for every combination. You cannot accidentally skip a row or column the way you might when writing a list. Every cell represents exactly one outcome, so counting is straightforward.

Worked example: Building a Sample Space Grid: Two Dice

Two fair six-sided dice are rolled. Find the probability that the total is 7.

  1. Label columns 1–6 (Die 1) and rows 1–6 (Die 2). — A 6-by-6 grid gives 6 × 6 = 36 cells in total — one for each equally likely outcome. [M1 for recognising 36 total outcomes]
  2. Each cell = (column value) + (row value). For example, column 3, row 4 gives 3 + 4 = 7. — Work row by row to avoid gaps. The grid fills with values from 2 (top-left: 1+1) to 12 (bottom-right: 6+6).
  3. Pairs that sum to 7: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) — that is 6 cells. — Highlight or circle these cells in the grid. Counting highlighted cells gives the favourable outcomes. [M1 for correct count of 6]
  4. $P(\text{total} = 7) = \dfrac{6}{36} = \dfrac{1}{6}$ — Favourable outcomes ÷ total outcomes. Simplify the fraction fully. [A1 for $\frac{1}{6}$]

Answer: $P(\text{total} = 7) = \dfrac{1}{6}$

The bar chart above confirms the grid: the total 7 appears more often than any other total, which is exactly what the grid reveals when you count highlighted cells. Grids do not just answer one question — they let you read off probabilities for any total at a glance.

3. Tables for Non-Numerical Combined Events

Grids work just as well when outcomes are not numbers. Suppose a bag contains a red (R), blue (B), and green (G) counter, and a spinner has sections labelled 1, 2, and 3. A table listing all counter-spinner combinations enumerates the full sample space of 3 × 3 = 9 outcomes without any guesswork.

Spinner 1Spinner 2Spinner 3
Red (R)R1R2R3
Blue (B)B1B2B3
Green (G)G1G2G3

From this table, questions like "what is the probability of picking a red counter and an odd number?" become a matter of counting: R1 and R3 are the favourable outcomes, giving $P = \frac{2}{9}$. The table has done the hard work of organisation; you supply the counting.

4. Venn Diagrams for Sets and Their Combinations

Tables and grids are ideal when two events produce independent outcomes. Venn diagrams take over when you need to show how groups of outcomes overlap — for example, which students study both French and Spanish, or which numbers are both even and multiples of 3.

A Venn diagram consists of a rectangle representing the universal set $\xi$ (everything under consideration) and circles inside it representing individual sets. Where two circles overlap, the overlapping region holds outcomes that belong to both sets simultaneously — the intersection $A \cap B$.

Four regions appear in any two-set Venn diagram: A only, B only, $A \cap B$ (both), and neither. Every outcome in the universal set must sit in exactly one of these four regions. If you place an outcome in two regions, you have made an error.

Worked example: Constructing a Venn Diagram from Given Information

In a class of 30 students, 18 study French (F), 14 study Spanish (S), and 7 study both. The rest study neither. Draw a Venn diagram and find $P(F \cup S)$.

  1. $F \cap S = 7$ students study both. — Place 7 in the overlapping region first — this is always the starting point when you know the intersection. [M1]
  2. $18 - 7 = 11$ students study French but not Spanish. — Subtract the intersection from the French total to get the left crescent only. Place 11 in the left region of circle F.
  3. $14 - 7 = 7$ students study Spanish but not French. — Subtract the intersection from the Spanish total. Place 7 in the right region of circle S.
  4. $30 - 11 - 7 - 7 = 5$ students study neither. — Total minus all three circle regions. Place 5 outside both circles but inside the rectangle. Check: 11 + 7 + 7 + 5 = 30. [M1 for correct diagram]
  5. $F \cup S = 11 + 7 + 7 = 25$ students. $P(F \cup S) = \dfrac{25}{30} = \dfrac{5}{6}$ — The union includes everyone in F, everyone in S, and those in both — but count the intersection only once. [A1 for $\frac{5}{6}$]

Answer: $P(F \cup S) = \dfrac{5}{6}$. Venn diagram regions: F only = 11, both = 7, S only = 7, neither = 5.

Notice the key move in Step 2 and Step 3: always subtract the intersection before placing values in the individual circle regions. Placing the full totals (18 and 14) directly into the circles is the most common error on this type of question — it double-counts the 7 students who study both subjects.

5. Reading Probabilities from Venn Diagrams

Once a Venn diagram is correctly filled in, it becomes a probability machine. Every region holds a count, and every probability is that count divided by the total in $\xi$. The skill is translating the probability notation into the correct region or combination of regions.

The complement rule $P(A') = 1 - P(A)$ is particularly useful on exam papers because it turns a complicated region into a simple subtraction. If finding $P(A)$ is straightforward, finding $P(A')$ costs you almost no extra effort.

6. Choosing the Right Tool and Exam Technique

Both grids and Venn diagrams are tools for systematic enumeration — the same underlying idea expressed differently. A grid suits two-event experiments where you list every combination (rolling dice, spinning spinners, drawing from bags). A Venn diagram suits set-membership problems where outcomes can belong to overlapping categories.

On an Higher-tier paper, the question usually signals which tool to use. Phrases like "draw a sample space diagram" or "complete the table" point to a grid. Phrases like "complete the Venn diagram" or "the sets A and B are shown" point to Venn diagrams. If neither is specified, choose whichever makes counting easier for the specific problem.

Frequently asked questions

What is a sample space diagram?

A sample space diagram is a two-way grid listing every outcome of two combined events, with one event across the top and the other down the side. For two dice it has 6 × 6 = 36 cells, and 6 of them total 7, so P(total = 7) = 6/36 = 1/6.

What is the complement of a set?

The complement A′ is everything in the universal set ξ that is not in A, shown on a Venn diagram as everything outside circle A. Use P(A′) = 1 - P(A) to turn a complicated region into a simple subtraction.

What is the intersection on a Venn diagram?

The intersection A ∩ B is the overlapping region of the two circles, holding outcomes that belong to both sets. A two-set Venn diagram has four regions: A only, B only, A ∩ B and neither, and every outcome sits in exactly one of them.

How do you fill in a Venn diagram?

Start with the intersection, then subtract it from each set total, then find the neither region. With 30 students, 18 studying French, 14 studying Spanish and 7 studying both, French only = 11, Spanish only = 7, both = 7 and neither = 5.

How do you find the probability of a union from a Venn diagram?

The union A ∪ B includes everything in A and everything in B, counting the intersection only once. With French only 11, both 7 and Spanish only 7 out of 30 students, P(F ∪ S) = 25/30 = 5/6.

What is the probability of getting a total of 7 with two dice?

The probability of a total of 7 with two fair dice is 1/6. A 6 by 6 grid gives 36 outcomes, and 6 of them total 7: (1,6), (2,5), (3,4), (4,3), (5,2) and (6,1), so P = 6/36 = 1/6.

What is the most likely total with two dice?

The most likely total when rolling two dice is 7, which appears in 6 of the 36 cells of the sample space grid. The totals range from 2 (1 + 1) to 12 (6 + 6).

How do you find the probability of a red counter and an odd number?

A table of 3 counters (red, blue, green) against a spinner showing 1, 2 and 3 gives 9 outcomes. Red with an odd number is R1 and R3, so the probability is 2/9.

How do you fill in a Venn diagram for French and Spanish?

For 30 students where 18 study French, 14 study Spanish and 7 study both, place 7 in the overlap first. Then French only is 18 - 7 = 11, Spanish only is 14 - 7 = 7, and neither is 30 - 25 = 5.

What is the universal set?

The universal set, ξ, is everything under consideration in a Venn diagram, shown as the rectangle. Every outcome must sit in exactly one region inside it, including the 'neither' region outside the circles.

What are the regions of a two-set Venn diagram?

A two-set Venn diagram has four regions: A only, B only, A ∩ B (both) and neither. Every outcome in the universal set sits in exactly one of these regions.

What is the most common mistake when filling in a Venn diagram?

The most common error is placing the full totals straight into the circles instead of subtracting the intersection first. This double-counts the outcomes in both sets, such as the 7 students studying both subjects.

Should you use a Venn diagram or a sample space grid?

A sample space grid suits two-event experiments where every combination is listed, such as rolling dice. A Venn diagram suits set-membership problems where outcomes can belong to overlapping categories.

What does A ∪ B mean on a Venn diagram?

A ∪ B, the union, means everything in A, in B or in both, counting the intersection only once. For French and Spanish with regions 11, 7 and 7, the union is 25 out of 30, so P = 5/6.

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